How do you solve $125^(2x+1)/625^(x+2)=3125^(x+2)$ ?

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Answer 1 · 2016-09-19T06:33:32

$x=-5$

$(125^(2x+1))/(625^(x+2))=3125^(x+2)$

or $((5^3)^(2x+1))/((5^4)^(x+2))=(5^5)^(x+2)$

or $(5^(3xx(2x+1)))/(5^(4xx(x+2)))=5^(5xx(x+2)$ ^

or $(5^(6x+3))/(5^(4x+8))=5^(5x+10)$

or $5^(6x+3-4x-8)=5^(5x+10)$

or $5^(2x-5)=5^(5x+10)$

or $2x-5=5x+10$

or $2x-5x=10+5$

or $-3x=15$

or $x=15/-3=-5$

How do you solve 125^(2x+1)/625^(x+2)=3125^(x+2)125^(2x+1)/625^(x+2)=3125^(x+2)?