How do you solve $12 x^{2} = 48 x$ $12x^2=48x$ ?

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Answer 1 · 2018-06-25T19:53:04

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Rearrange:

$12 x^{2} - 48 x = 0$ $12x^2-48x =0$

Factor out the $x$ $x$ :

$x (12 x - 48) = 0$ $x(12x-48) = 0$

Hence product of two polynomials equaling 0 means

$x = 0$ $x = 0$

and

$12 x - 48 = 0$ $12x - 48 = 0$

$12 x = 48 \Rightarrow x = \frac{48}{12}$ $12x = 48 => x= 48/12$

$x = 0$ $x = 0$ and $x = 4$ $x= 4$

How do you solve 12x^2=48x12x2=48x12x^2=48x?