How do you solve $12 x^{2} - 6 x = 0$ $12x^2 - 6x = 0$ ?

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Answer 1 · 2018-03-13T12:40:12

See a solution process below:

First, factor an $6 x$ $6x$ from each term on the left side of the equation:

$(6 x \cdot 2 x) - (6 x \cdot 1) = 0$ $(6x * 2x) - (6x * 1) = 0$

$6 x (2 x - 1) = 0$ $6x(2x - 1) = 0$

Now, solve each term on the left for $0$ $0$ :

Solution 1:

$6 x = 0$ $6x = 0$

$\frac{6 x}{6} = \frac{0}{6}$ $(6x)/color(red)(6) = 0/color(red)(6)$

$(color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6)) = 0$

$x = 0$

Solution 2:

$2x - 1 = 0$

$2x - 1 + color(red)(1) = 0 + color(red)(1)$

$2x - 0 = 1$

$2x = 1$

$(2x)/color(red)(2) = 1/color(red)(2)$

$(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 1/2$

$x = 1/2$

The Solution Set Is: $x = {0, 1/2}$

How do you solve 12x^2 - 6x = 012x2−6x=012x^2 - 6x = 0?