How do you solve $12x^2 - 7x + 1 = 0$ ?

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Answer 1 · 2016-03-31T17:35:43

The solutions are:

$color(green)(x= 1/3$

$color(green)(x= 1/4$

$12x^2 - 7x + 1 = 0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=12, b=-7, c=1$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (-7)^2-(4* 12 * 1)$

$= 49 - 48 = 1$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-7)+-sqrt(1))/(2*12) = (7+- 1 )/24$

$x= (7+1) / 24= 8/24 = 1/3$

$x= (7-1) / 24= 6/24 = 1/4$

How do you solve 12x^2 - 7x + 1 = 0 12x^2 - 7x + 1 = 0 ?