How do you solve $13n-n^2=0$ ?

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Answer 1 · 2016-03-31T17:25:39

The solutions are:

$color(blue)( n =0$

$color(blue)(n =13$

$13n - n^2 =0$

Multiplying the entire equation by $-1$ :

$n^2 - 13n =0$

$n$ is common to both terms of the L.H.S :

$n ( n - 13 ) =0$

Equating each of the factors to zero, we obtain the solutions:

$color(blue)( n =0$

$n - 13 =0, color(blue)(n =13$

Answer 2 · 2016-03-31T17:26:28

$n=0 or n=13$

Start by factorizing to get

$n(13-n)=0$

$therefore n=0 or n=13$

How do you solve 13n-n^2=013n-n^2=0?