How do you solve #14> - 2x + 2> - 4#?
1 Answer
Apr 19, 2018
Explanation:
#"subtract 2 from each interval"#
#14color(red)(-2)> -2xcancel(+2)cancel(color(red)(-2))> -4color(red)(-2)#
#rArr12> -2x > -6#
#"divide all 3 intervals by "-2#
#color(red)"Remembering to reverse the inequality signs"#
#rArr-6 < x < 3#
#x in (-6,3)larrcolor(blue)"in interval notation"#
