How do you solve $14x^2+3x-2=0$ ?

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Answer 1 · 2015-07-08T09:27:58

The solutions are
$color(blue)(x=2/7 , x=-1/2$

$14x^2 + 3x -2 = 0$

We can first factorise the equation and then find the solutions :

Factorising by splitting the middle term:

$14x^2 + 3x -2 = 0$

$14x^2 + color(blue)(7x -4x) -2 = 0$

$7x (2x+1) -2 (2x+1) = 0$

$color(blue)((7x -2)(2x+1) = 0$

Now, equating the factors with zero to obtain the solutions
$7x -2 = 0 , color(blue)(x=2/7$
$2x+1 = 0 ,color(blue)( x =-1/2$

How do you solve 14x^2+3x-2=0 14x^2+3x-2=0?