How do you solve $15-20x²=0$ ?

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Answer 1 · 2018-03-31T03:44:46

Solution: $x= sqrt3/2 and x= - sqrt3/2$

$15-20x^2=0 or 20x^2=15$ or

$x^2=15/20 or x^2 = 3/4$

$:.x =+- sqrt(3/4):. x= sqrt3/2 and x= - sqrt3/2$

Solution: $x= sqrt3/2 and x= - sqrt3/2$ [Ans]

How do you solve 15-20x²=015-20x²=0?