How do you solve $-15x^2 + 18x = 0$ ?

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Answer 1 · 2018-04-30T22:24:51

First factor: $0 = -15 x^2 + 18 x = -3 x(5x - 6)$ so $x=0$ or $5x-6=0$ , that is, $x=6/5.$

Check:

$-15(0)^2 + 18(0) = 0 quad sqrt$

$-15(6/5)^2 + 18(6/5)$

$= -15(36/25) + {3(36)}/5$

$= -{3(36)}/5 + {3(36)}/5 = 0 quad sqrt$

How do you solve -15x^2 + 18x = 0-15x^2 + 18x = 0?