How do you solve -16+0.2(10^x)=3516+0.2(10x)=35?

1 Answer

x=log255~~2.407x=log2552.407

Explanation:

-16+0.2(10^x)=3516+0.2(10x)=35

Let's move all the non-x terms to the right side:

0.2(10^x)=510.2(10x)=51

10^x=51/0.2=25510x=510.2=255

Now we can take the log of both sides:

log10^x=log255log10x=log255

xlog10=log255xlog10=log255

Remember that Log_(10)10=1log1010=1, so:

x=log255~~2.407x=log2552.407