How do you solve $16^b=88$ ?

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Answer 1 · 2016-09-15T02:57:30

$b=1.61486.....$

$16^b=88$
$blog_10(16)=log_10(88)$
$=> b=log_10(88)/log_10(16)$

$=> b=1.61486....$

How do you solve 16^b=8816^b=88?