How do you solve $-16x^2 - 144x – 320 = 0$ ?

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Answer 1 · 2015-06-25T14:45:40

x= -5, -4

Divide the equation by -16 to get $x^2 +9x +20=0$

Now split the middle term as $x^2 +5x +4x+20=0$

x(x+5) +4(x+5)=0

(x+5)(x+4)=0

x= -5, -4

How do you solve -16x^2 - 144x – 320 = 0-16x^2 - 144x – 320 = 0?