How do you solve $- 16x^2 + 36 = 0$ ?

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Answer 1 · 2015-06-15T11:55:17

$color(blue)(x = +-3/2$

$- 16x^2 + 36 = 0$
$16x^2 - 36 = 0$

Taking out a common term:
$4(4x^2 -9) = 0$
$4x^2 -9= 0$

$x^2 = 9/4$

$x = sqrt(9/4)$
$color(blue)(x = +-3/2$

How do you solve - 16x^2 + 36 = 0- 16x^2 + 36 = 0?