How do you solve $18 x^{2} + 48 x = - 32$ $18x^2+48x=-32$ ?

Question

How do you solve $18 x^{2} + 48 x = - 32$ $18x^2+48x=-32$ ?

1 Answer

Impact of this question

2316 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-12T14:04:25

Double-root: at $x = - \frac{4}{3}$ $x = -4/3$

Explanation:

Bring the equation to standard form after simplification by 2
$f (x) = 9 x^{2} + 24 x + 16 = {(3 x + 4)}^{2} = 0$ $f(x) = 9x^2 + 24x + 16 = (3x + 4)^2 = 0$
The 2 roots are: $\pm (3 x + 4) = 0$ $+- (3x + 4) = 0$
There is double-root at $x = - \frac{4}{3}$ $x = - 4/3$

Science

Math

Humanities

... and beyond

How do you solve $18 x^{2} + 48 x = - 32$ $18x^2+48x=-32$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve 18x^2+48x=-3218x2+48x=−3218x^2+48x=-32?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $18 x^{2} + 48 x = - 32$ $18x^2+48x=-32$ ?