How do you solve $–2(2x – 3) = –6$ ?

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Answer 1 · 2015-09-10T22:44:53

$x=3$

the question:

$–2(2x–3)=–6$

multiply the "internals" of the parentheses by the -2 to remove the parentheses:

$–4x+6=–6$

subtract 6 from both sides to remove it from the left:

$–4x+6-6=–6-6$

the answer so far is:

$–4x=–12$

divide both sides by $-4$ to remove it from the $x$ :

$-4x/-4=-12/-4$

the answer:

$x=3$

How do you solve –2(2x – 3) = –6–2(2x – 3) = –6?