How do you solve $\frac{2}{3} - \frac{1}{6}$ $2/3-1/6$ ?

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How do you solve $\frac{2}{3} - \frac{1}{6}$ $2/3-1/6$ ?

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Answer 1 · 2016-04-20T09:39:14

Make them both have the same denominator.

Explanation:

So make them both have $6$ $6$ on the bottom. Then change $\frac{2}{3}$ $2/3$ into a denominator of $6$ $6$ so

$3 \times 2 = 6$ $3 xx 2 = 6$

$2 \times 2 = 4$ $2 xx 2 = 4$

So it is now

$\frac{2}{3} = \frac{4}{6}$ $2/3 = 4/6$

Subtract $\frac{1}{6}$ $1/6$ from $\frac{4}{6}$ $4/6$ to basically get $4 - 1$ $4-1$ , which is $3$ $3$ , and keep the denominator the same. The answer is $\frac{3}{6}$ $3/6$ , which simplified is $\frac{1}{2}$ $1/2$

$\frac{4}{6} - \frac{1}{6} = \frac{4 - 1}{6} = \frac{3}{6} = \frac{1}{2}$ $4/6 - 1/6 = (4-1)/6 = 3/6 = 1/2$

Hope you get it :)

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