How do you solve $- 2.3 \cdot e^{- 6 m - 10} = - 38.8$ $-2.3*e^(-6m-10)=-38.8$ ?

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Answer 1 · 2017-01-25T11:07:15

$m = - \frac{1}{6} (10 + ln (\frac{38.8}{2.3})) = - 2.1376$ $m =- 1/6(10+ln(38.8/2.3))=-2.1376$ , nearly.

Here,

$e^{- (6 m + 10)} = \frac{38.8}{2.3}$ $e^(-(6m+10))=38.8/2.3$ . Inversely,

- $6 m - 10 = ln (\frac{38.8}{2.3})$ $6m-10=ln(38.8/2.3)$ , giving

$m = - \frac{1}{6} (10 + ln (\frac{38.8}{2.3}))$ $m= -1/6(10+ln(38.8/2.3))$

How do you solve −2.3⋅e−6m−10=−38.8-2.3*e^(-6m-10)=-38.8?