How do you solve $2/3 x^2 + 1/4 x= 3$ ?

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Answer 1 · 2016-01-25T12:23:24

$x=(-3+-3sqrt(129))/16$

First simplify $2/3x^2+1/4x=3$ by multiplying everything by $12$ to clear the fractions:

$8x^2+3x=36$

Re-write in standard $ax^2+bx+c=0$ form
$8x^2+3x-36=0$

Apply the quadratic formula $x=(-b+-sqrt(b^2-4ac))/(2a)$ to obtain the roots.

$x=(-3+-sqrt(9-4(8)(-36)))/(2(8))$

Simplify
$x=-(3+-3sqrt(129))/16$

How do you solve 2/3 x^2 + 1/4 x= 32/3 x^2 + 1/4 x= 3?