How do you solve $\frac{2}{3} (x - 2) = 4 x$ $2 / 3 (x − 2) = 4x$ and find any extraneous solutions?

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Answer 1 · 2017-04-22T20:00:13

$x = - \frac{2}{5}$ $x = -2/5$

Multiply both sides of the equation by $\frac{3}{2}$ $3/2$

$cancel3/cancel2 xxcancel2/cancel3(x-2) = 3/cancel2xx cancel4^2x$

$x-2 = 6x$

$-2 = 5x" "larr div 5$

$-2/5 =x$

$x$ is not in the denominator and there are no restrictions on $x$ , therefore there are no extraneous solutions.

How do you solve 2 / 3 (x − 2) = 4x 23(x−2)=4x2 / 3 (x − 2) = 4x and find any extraneous solutions?