How do you solve $2/3e^(4x)+1/3=4$ ?

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Answer 1 · 2016-08-07T04:42:45

Let's start by isolating the $e^(4x)$ .

$2/3e^(4x) = 4 - 1/3$

$2/3e^(4x) = 11/3$

$e^(4x) = (11/3)/(2/3)$

$e^(4x) = 11/2$

$ln(e^(4x)) = ln(11/2)$

$4x(ln(e)) = ln(11/2)$

$4x = ln(11/2)$

$x = 1/4ln(11/2)$

Hopefully this helps!

How do you solve 2/3e^(4x)+1/3=42/3e^(4x)+1/3=4?