How do you solve $- 2 < 4 z + 10 \leq 12$ $-2 < 4z + 10 ≤ 12$ ?

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How do you solve $- 2 < 4 z + 10 \leq 12$ $-2 < 4z + 10 ≤ 12$ ?

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Answer 1 · 2015-06-08T00:55:27

$- 2 < 4 z + 10 \leq 12$ $-2<4z+10<=12$
Subtract 10 from all the 3 members:
$- 2 - 10 < 4 z + 10 - 10 \leq 12 - 10$ $-2-10<4z+10-10<=12-10$
$- 12 < 4 z \leq 2$ $-12<4z<=2$
Devide by 4 all the three members:
$- 3 < z \leq \frac{1}{2}$ $-3< z <=1/2$
That's all folks!

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How do you solve $- 2 < 4 z + 10 \leq 12$ $-2 < 4z + 10 ≤ 12$ ?

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