How do you solve $2^(5n-5)+2=75$ ?

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Answer 1 · 2016-09-12T23:32:54

$2^(5n - 5) = 73$

$log(2^(5n - 5)) = log73$

$(5n - 5)log2 = log73$

$5nlog2 - 5log2 = log73$

$5nlog2 = log73 + log32$

$n= log2336/log32$

The decimal approximation will be $n ~=2.24$ .

Hopefully this helps!

How do you solve 2^(5n-5)+2=752^(5n-5)+2=75?