How do you solve $2(7x + 18) − 1 = (x + 6)^2$ ?

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Answer 1 · 2018-03-12T03:28:36

The solution is $x=1$ .

Expand the multiplication and then factor the leftover polynomial:

$color(red)2(7x + 18) − 1 = (x + 6)^2$

$color(red)2*7x+color(red)2*18-1=(x+6)^2$

$14x+36-1=(x+6)^2$

$14x+35=(x+6)(x+6)$

$14x+35=x^2+6x+6x+36$

$14x+35=x^2+12x+36$

$35=x^2-2x+36$

$0=x^2-2x+1$

$0=(x-1)^2$

$sqrt0=sqrt((x-1)^2)$

$0=x-1$

$x=1$

How do you solve 2(7x + 18) − 1 = (x + 6)^22(7x + 18) − 1 = (x + 6)^2?