How do you solve $2 - a - 4 a = 12$ $2- a - 4a = 12$ ?

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Answer 1 · 2016-10-28T00:47:41

$a = - 2$ $a=-2$

$2 - a - 4 a = 12$ $2-a-4a=12$

$- a - 4 a = 12 - 2$ $-a-4a=12-2$

$- 5 a = 10$ $-5a=10$

$a = \frac{10}{- 5}$ $a=10/-5$

$a = - 2$ $a=-2$

How do you solve 2- a - 4a = 122−a−4a=122- a - 4a = 12?