How do you solve 2+log3(2x+5)log3x=4?

1 Answer
Feb 8, 2015

I would start by collecting the logs on one side:

log3(2x+5)log3(x)=42

I can use the fact that:
logM+logN=log(MN)
Giving:

log3(2x+5x)=2

Use the definition of logarithm:

logax=bab=x

Giving:

2x+5x=32
2x+5=9x
7x=5
x=57

hope it helps