How do you solve $2(x - 1)^2 - 8(x - 1)^2= 0$ ?

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Answer 1 · 2015-05-21T07:53:02

$(x-1)^2$ is common to both the terms of the expression on the left hand side

We can write the equation as $(x-1)^2*(2-8) = 0$

$->-6(x-1)^2 = 0$

Dividing both sides by $-6$ we get:

$->(cancel(-6)(x-1)^2)/cancel(-6) = 0/-6$

$->(x-1)^2 = 0$

$->x-1=0$

$-> color(green)(x = 1$

How do you solve 2(x - 1)^2 - 8(x - 1)^2= 02(x - 1)^2 - 8(x - 1)^2= 0?