How do you solve $2(x-3)^2 = 3$ ?

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Answer 1 · 2016-05-14T20:24:26

$x = 3+-sqrt(6)/2$

Divide both sides by $2$ to get:

$(x-3)^2 = 3/2 = 6/4$

Take the square root of both ends, allowing either sign:

$x-3 = +-sqrt(6/4) = +-sqrt(6)/sqrt(4) = +-sqrt(6)/2$

Add $3$ to both ends to get:

$x = 3+-sqrt(6)/2$

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