How do you solve $2^(x-9) = 5$ ?

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Answer 1 · 2016-08-12T21:58:49

$x=11.3223$

As $2^(x-9)=5$ , writing in logarithmic form we have

$(x-9)=log_2(5)$ , which can be also written as

$(x-9)=log5/log2$

= $0.6990/0.3010=2.3223$

and $x=9+2.3223=11.3223$

How do you solve 2^(x-9) = 5 2^(x-9) = 5 ?