How do you solve $20^{- 6 n} + 6 = 55$ $20^(-6n)+6=55$ ?

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Answer 1 · 2016-11-22T19:25:32

$n = - \frac{1}{6} {log}_{20} (49)$ $n=-1/6log_20(49)$
$n \approx - .2165$ $napprox-.2165$

$20^{- 6 n} + 6 = 55$ $20^(-6n)+6=55$

Subtract 6 from each side:
$20^{- 6 n} = 49$ $20^(-6n)=49$

Rewrite as a log:
${log}_{20} (49) = - 6 n$ $log_20(49)=-6n$

$n = - \frac{1}{6} {log}_{20} (49)$ $n=-1/6log_20(49)$

How do you solve 20^(-6n)+6=5520−6n+6=5520^(-6n)+6=55?