How do you solve $25a=10a^2$ ?

Question

3995 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-24T23:50:44

$=>a=5/2$

We are given

$25 a = 10a^2$

First we divide both sides by $a$ :

$(25cancela)/cancela = (10a^cancel(2))/cancela$

$25 = 10a$

Then we divide both sides by $10$ :

$25/10 = (cancel(10)a)/cancel(10)$

$5/2 = a$

Answer 2 · 2018-04-24T23:51:21

$a=0,5/2$

We can start by subtracting $25a$ from both sides to get

$10a^2-25a=0$

We can factor out a $5a$ to get

$5a(2a-5)=0$

We now set both factors equal to zero:

$5a=0=>color(blue)(a=0)$

$2a-5=0=>2a=5=>color(blue)(a=5/2)$

Hope this helps!

How do you solve 25a=10a^225a=10a^2?