Question

How do you solve `27x² - 12 = 0`?

Answer 1

Get the `x^2` by itself, then take square root of both sides.

Explanation:

`27x^2-12=0`
First, add 12 to both sides: `27x^2 = 12`
Second, divide both sides by 27: `x^2 = 12/27`
Third, reduce the fraction to lowest terms: `x^2 = 4/9`
Fourth, take `+-` the square root of both sides: `x=+-sqrt(4/9)`
Fifth, simplify the square roots: `x=+-2/3`

The solution set is `[-2/3, 2/3]`