How do you solve $- 29 = - 5 (1 + 6 b) + 6 (3 b - 4)$ $-29= - 5( 1+ 6b ) + 6( 3b - 4)$ ?

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Answer 1 · 2018-04-15T04:53:31

$b = 0$ $color(purple)(b = 0$

-30 b + 18 b = -29 + 5 + 24, color(indigo)(" bringing like terms together"#

$- 12 b = 0 or b = 0$ $-12 b = 0 " or " b = 0$
-5(1 + 6b) + 6 (3b - 4) = -29#

![https://www.mathematics-monster.com/lessons/order_of_operations.html]( useruploads.socratic.org )

Order of operations as above.

$- 5 - 30 b + 18 b - 24 = - 29, removing brackets$ $-5 - 30 b + 18 b - 24 = -29, color(crimson)(" removing brackets"$

How do you solve −29=−5(1+6b)+6(3b−4)-29= - 5( 1+ 6b ) + 6( 3b - 4)?