How do you solve $2abs(3x - 2 ) = 14$ ?

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Answer 1 · 2015-06-28T19:58:50

There are two possible answers:

$x_1=3$

$x_2=-5/3$

$2abs(3x-2)=14 rarr abs(3x-2)=7$

Knowing that $abs(x)=abs(-x)$ we now have two possibilities:

$3x-2=7$ or
$3x-2=-7$

I) $3x-2=7 rarr 3x=7+2=9 rarr x=9/3=3$

II) $3x-2=-7 rarr 3x=-7+2=-5 rarr x=-5/3$

How do you solve 2abs(3x - 2 ) = 142abs(3x - 2 ) = 14?