How do you solve $-2e^(7v+5)-10=-17$ ?

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Answer 1 · 2018-05-14T12:34:54

Solution : $v ~~ -0.535$

$-2 e^(7 v+5) -10 = -17$ or

$-2 e^(7 v+5) = 10-17$ or

$e^(7 v+5) = 7/2$ Taking natural log on both sides we get,

$(7 v+5) ln e = (ln 7 - ln 2) ; [ln e =1]$

$:. (7 v+5) ~~ 1.253 ;$

$:. 7 v ~~ 1.253-5 or 7 v ~~ -3.75 ;$

$:. v ~~ -3.75/7 ~~ -0.535 (3dp)$

Solution : $v ~~ -0.535$ [Ans]

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