How do you solve $2e^(8x)=45$ ?

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Answer 1 · 2016-09-30T02:49:38

$e^(8x) = ln(45/2)$

$e^(8x) = 22.5$

$ln(e^(8x)) = ln22.5$

$8xlne = ln22.5$

$8x = ln22.5$

$x = ln22.5/8$

$x ~=0.39$

Hopefully this helps!

How do you solve 2e^(8x)=452e^(8x)=45?