How do you solve $2 e^{x} - 1 = 11$ $2e^x-1=11$ ?

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Answer 1 · 2016-09-20T19:28:46

$x = ln 6$ $x=ln6$

$2 e^{x} - 1 = 11$ $2e^x-1=11$

$therefore 2e^x=12$

$therefore e^x=6$

$therefore lne^x=ln6$

$therefore xlne=ln6$

$therefore x=ln6$

How do you solve 2e^x-1=112ex−1=112e^x-1=11?