How do you solve $2 e^{x} - 5 = 1$ $2e^x-5=1$ ?

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Answer 1 · 2017-01-02T04:31:33

$x = ln 3$ $x = ln 3$

$2 e^{x} - 5 = 1$ $2e^x - 5 = 1$

$\Rightarrow 2 e^{x} = 6$ $=> 2e^x = 6$

$\Rightarrow e^{x} = 3$ $=> e^x = 3$

$\Rightarrow ln (e^{x} = 3)$ $=> ln(e^x = 3)$

$\Rightarrow x = ln 3$ $=> x = ln 3$

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