How do you solve $2Ln(x(18)+1)=2.3$ ?

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Answer 1 · 2016-04-14T08:17:48

$x=0.12$

As $2ln(x(18)+1)=2.3$

$ln(18x+1)=2.3/2=1.15$

$18x+1=e^1.15=3.1582$

$therefore 18x=2.1582$ and

$x=2.1582/18=0.12$

How do you solve 2Ln(x(18)+1)=2.32Ln(x(18)+1)=2.3?