How do you solve 2n^2-50=0?

1 Answer
Mar 10, 2018

See a solution process below:

Explanation:

First, add color(red)(50) to each side of the equation to isolate the n term while keeping the equation balanced:

2n^2 - 50 + color(red)(50) = 0 + color(red)(50)

2n^2 - 0 = 50

2n^2 = 50

Next, divide each side of the equation by color(red)(2) to isolate n^2 while keeping the equation balanced:

(2n^2)/color(red)(2) = 50/color(red)(2)

(color(red)(cancel(color(black)(2)))n^2)/cancel(color(red)(2)) = 25

n^2 = 25

Now, take the square root of each side of the equation to solve for n while keeping the equation balanced. Remember, the square root of a number produces a positive and negative result.

sqrt(n^2) = +-sqrt(25)

n = +-5

The Solution Set Is:

n = {-5, 5}