How do you solve - 2r + 6( r - 1) + 3r - ( 4- r ) = - ( r + 5)2r+6(r1)+3r(4r)=(r+5)?

1 Answer
Jan 28, 2017

See the entire solution process below:

Explanation:

First, expand the terms within parenthesis on both sides of the equation:

-2r + 6r - 6 + 3r - 4 + r = -r - 52r+6r6+3r4+r=r5

Next, group and combine like terms on the left side of the equation:

-2r + 6r + 3r + r - 6 - 4 = -r - 52r+6r+3r+r64=r5

(-2 + 6 + 3 + 1)r - 10 = -r - 5(2+6+3+1)r10=r5

8r - 10 = -r - 58r10=r5

Then, add color(red)(r)r and color(blue)(10)10 to each side of the equation to isolate the rr terms while keeping the equation balanced:

8r - 10 + color(red)(r) + color(blue)(10) = -r - 5 + color(red)(r) + color(blue)(10)8r10+r+10=r5+r+10

8r + color(red)(r) - 10 + color(blue)(10) = -r + color(red)(r) - 5 + color(blue)(10)8r+r10+10=r+r5+10

9r - 0 = 0 + 59r0=0+5

9r = 59r=5

Now, divide each side of the equation by color(red)(9)9 to solve for rr while keeping the equation balanced:

(9r)/color(red)(9) = 5/color(red)(9)9r9=59

(color(red)cancel(color(black)(9))r)/cancel(color(red)(9)) = 5/9

r = 5/9