How do you solve (2u+7)(3u-1)=0?
1 Answer
Apr 16, 2018
u=(-7)/2
u=1/3
Explanation:
Given
(2u+7)(3u-1)=0
2u+7=0
2u=-7
u=(-7)/2
(3u-1)
3u=1
u=1/3
u=(-7)/2
u=1/3
Given
(2u+7)(3u-1)=0
2u+7=0
2u=-7
u=(-7)/2
(3u-1)
3u=1
u=1/3