How do you solve $2x² + 10 = 9x$ ?

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Answer 1 · 2016-04-10T16:44:42

The solutions are:
$x = 2$

$x = 5/2$

$2x^2 + 10 = 9x$

$2x^2 -9x + 10 = 0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:

$a= 2 , b=- 9 , c= 10$

The Discriminant is given by:
$Delta=b^2-4*a*c$
$= (-9)^2-(4 * 2 * 10)$
$= 81 - 80 = 1$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-9)+-sqrt(1))/(2 * 2 ) = (9+-1)/ 4$

$x = (9 - 1 ) / 4 = 8/4 = 2$

$x = (9 + 1 ) / 4 = 10/4 = 5/2$

How do you solve 2x² + 10 = 9x2x² + 10 = 9x?