How do you solve 2x ^ { 2} + 10x - 168= 0? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer sankarankalyanam Oct 16, 2017 **x = -12, 7** Explanation: 2x^2+10x-168=0. Dividing by 2, x^2+5x-84=0 x^2+12x-7x-84=0 x(x+12)-7(x+12)=0 (x+12)(x-7)=0 x = -12, 7 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1908 views around the world You can reuse this answer Creative Commons License