How do you solve 2x^2+11x+5=0?

1 Answer
Apr 11, 2018

x=-5" or "x=-1/2

Explanation:

"using the a-c method to factorise"

"consider the factors of the product "2xx5=10
"which sum to + 11"

"the required factors are + 10 and + 1"

"split the middle term using these factors"

2x^2+10x+x+5=0larrcolor(blue)"factor in groups"

rArrcolor(red)(2x)(x+5)color(red)(+1)(x+5)=0

"take out the common factor "(x+5)

rArr(x+5)(color(red)(2x+1))=0

"equate each factor to zero and solve for x"

x+5=0rArrx=-5

2x+1=0rArrx=-1/2