How do you solve $2 x^{2} - 12 x + 18 = 32$ $2x^2 - 12x + 18 = 32$ ?

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How do you solve $2 x^{2} - 12 x + 18 = 32$ $2x^2 - 12x + 18 = 32$ ?

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Answer 1 · 2016-05-06T13:17:28

x = -1 and x = 7

Explanation:

$y = 2 x^{2} - 12 x - 14 = 0$ $y = 2x^2 - 12x - 14 = 0$
$y = 2 (x^{2} - 6 x - 7) = 0$ $y = 2(x^2 - 6x - 7) = 0$
Solve the quadratic equation in parentheses.
Since a - b + c = 0, use shortcut. The 2 real roots are: - 1 and
$- \frac{c}{a} = 7 .$ $-c/a = 7.$

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How do you solve $2 x^{2} - 12 x + 18 = 32$ $2x^2 - 12x + 18 = 32$ ?

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Explanation:

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How do you solve 2x^2 - 12x + 18 = 322x2−12x+18=322x^2 - 12x + 18 = 32?

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How do you solve $2 x^{2} - 12 x + 18 = 32$ $2x^2 - 12x + 18 = 32$ ?