How do you solve $2x^2-13x-7=0$ ?

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Answer 1 · 2016-03-22T18:04:26

$x = -1/2 or 7$

$2x^2-13x-7=0$
can be factored to
$(2x+1)(x-7)=0$
set each factor equal to zero and solve for $x$
$2x+1=0$

$2x+1-1=0-1$

$2x=-1$

$(cancel2x)/cancel2 =-1/2$

$x = -1/2$

$x-7=0$

#x-7+7=0+7

$x=7$

$x = -1/2 or 7$

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