How do you solve $2x^2-13x-7=0$ ?

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Answer 1 · 2016-06-04T03:40:49

$x = -1/2 or x= 7$

The trinomial $2x^2-13x-7=0$ can be factored

$(2x +1)(x-7)=0$

Now set each factor equal to zero

$2x+1=0$

$2xcancel(+1)cancel(-1)=0-1$

$2x=-1$

$(cancel(2)x)/cancel2=-1/2$

$x=-1/2$

and $x-7=0$

$xcancel(-7)cancel(+7)= 0+7$

$x = 7$

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