How do you solve #-2x^2 = -162#?
1 Answer
Apr 16, 2017
Explanation:
#color(blue)"Isolate " x^2" by dividing both sides by " -2#
#(cancel(-2) x^2)/cancel(-2)=(-162)/(-2)#
#rArrx^2=81#
#color(blue)"take the square root of both sides"#
#sqrt(x^2)=color(red)(+-)sqrt81#
#rArrx=color(red)(+-)9#
#["Note the " +-" solutions"]#
#color(blue)"As a check"# Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
#x=color(red)(+9)to-2xx(color(red)(+9))^2=-2xx81=-162#
#x=color(red)(-9)to-2xx(color(red)(-9))^2=-2xx81=-162#
#rArrx=+-9" are the solutions"#