Question

How do you solve `2x^2+5=41`?

Answer 1

`x=+-3sqrt2`

Explanation:

`"isolate "2x^2" by subtracting 5 from both sides"`

`rArr2x^2=41-5=36`

`"divide both sides by 2"`

`rArrx^2=36/2=18`

`color(blue)"take the square root of both sides"`

`sqrt(x^2)=+-sqrt18larrcolor(blue)"note plus or minus"`

`rArrx=+-sqrt18=+-3sqrt2`