How do you solve $2x^2+5x+2=0$ ?

Question

5929 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-12T16:36:11

$color(blue)(x=-1/2,x=-2$

$2x^2+5x+2$

Here, we can first factorise the expression and then find the solutions.

Factorising by splitting middle term

$2x^2+color(green)(5x)+2=0$

$2x^2+color(green)(4x +x)+2=0$

$2x(x+2)+1(x+2)=0$

$(2x+1)(x+2)=0$
Now, we equate the factors with zero to find the solutions.

$2x+1=0, color(blue)(x=-1/2$
$x+2=0 , color(blue)(x=-2$

How do you solve 2x^2+5x+2=02x^2+5x+2=0?